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mmh A boat has a mass of 6800 kg. Its engines generate a drive force of 4100 N due west, while the wind exerts a force of 800 N due east andthe water exerts a resistive force of 1200 N due east. What are the magnitude and direction of the boat’s acceleration?

$+0.31 \mathrm{m} / \mathrm{s}^{2}$due west

Physics 101 Mechanics

Chapter 4

Forces and Newton’s Laws of Motion

Newton's Laws of Motion

Applying Newton's Laws

University of Michigan - Ann Arbor

University of Washington

McMaster University

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in this question that our three forces acting on a boot, one force acting towards the east direction with 4000 and 100 neuters another force acts to the east direction. We state 100 noodles on the third force acts to the each direction With 1000 and 200 Newtons, this force is produced by the votes and giant. This force is producing by the wind and this forces produce it by the resistance of the water. Then what are the magnitude and the direction off the boats exploration? What you have to do before doing anything else is to discover one is the net force that acts on that boat. Then that force is Halloween. That's next because to the some off the street forces let us see that everyone that is going to tease this positive then as a consequence, everyone responding to the West will be negative. This is a choice. These will not change. If you mix up the problem, then the net force is He goes to 800 blood, 1200 plus not blush. Now we have a minus because these forces is pointing to the West direction which is the negative connection so minus 4000 and 100 and this gives us a net force. That is the question of minors. 2000 and 100 new tops. Now we can use Newton's second law to copulate acceleration off that boat. According to Newton's second hole, the net force being close to the master kind exploration off the boat. We know what is the matter of the boat. Then we can Copley the acceleration as follows. Operation off the boat will be equal to the net force divided by that match off the boot. This is a question minus 2100 divided by 6800. Then this gives us an acceleration off approximately minus zero 0.31 meters. 1st 2nd square, then acceleration magnitude is 0.31 meters per second and it has a negative sign in front of it. For the direction of acceleration is the negative direction, which the way direction, So the answer it will be. The following inactivation is 0.31 meters per second squared do west

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